Star–delta changeover: timer setting and interlock
CHIEF. LEARN · Guide 3 of 6
The star–delta changeover step by step, how to set the timer (80–90 % of synchronous speed) and why the star and delta contactors must never close together.
The example throughout is the main fire pump of a platform supply vessel: a 37 kW cage motor on a 440 V, 60 Hz supply, full-load current 61 A, started star–delta from the main switchboard.
- MC
- main contactor
- SC
- star contactor
- DC
- delta contactor
- T
- star–delta timer relay
- MCCB
- moulded-case circuit breaker
- NC / NO
- normally closed / normally open contact
The changeover, step by step
- START: MC and SC pick up. The motor runs in star and the timer T starts counting.
- T times out: its delayed NC contact 55–56 opens and SC drops out. Its delayed NO contact 67–68 closes only 50 ms later. Star–delta timer relays have this dead time built in: it lets the arc on SC’s opening contacts go out before delta closes.
- DC picks up only when 67–68 has closed and SC is fully open, because SC’s NC contact sits in DC’s coil circuit. For well under a tenth of a second the motor is connected to nothing and coasts. Then it is in delta.
- DC holds itself in with its own NO contact and drops out T with its NC contact. The start is finished.
The open transition
That gap is called an open transition. While the supply is off, the rotor field decays and drifts out of step with the supply. When delta closes, the difference causes a second surge. The faster the motor turns at that moment, the smaller the surge.
The simulator’s charts show only the slip current of that second surge. The short transient from the residual rotor voltage is left out, so real changeover peaks can be higher.
Setting the timer
The timer decides at what speed the motor changes over. A common rule is to change over at 80–90 % of synchronous speed, or once the star current has fallen back to about full-load current. On this pump the simulator asks for at least 86 %.
Too short, and the motor is still slow when delta closes. The second surge then comes close to a direct-on-line start, and the point of star–delta is lost.
Too long gains nothing. The motor has already reached the speed where star torque equals the pump load, and it carries on at a third of its torque with extra slip and extra heat in the windings.
The simulator charts the changeover surge against the timer setting for this pump with all four hydrants open, the heaviest load and the one its starter check uses.
SC and DC must never be closed together
SC joins W2, U2 and V2 into the star point. DC connects the same three terminals to L1, L2 and L3. With both closed at once, the three phases are tied together through the star bar: a bolted short circuit inside the starter.
The fault current runs to several kA, far above the MCCB’s instantaneous release, so the MCCB trips at once. Even so, the arc may already have welded the main contacts and damaged the starter.
Three things keep them apart: an NC auxiliary contact of each contactor in the other’s coil circuit (the interlock in rungs 3 and 4 of the control circuit), a mechanical interlock between the two contactors on many starters, and the dead time at the changeover.
Mirror contacts: a starter stuck in star
On most modern contactors the NC auxiliary contacts are mirror contacts (IEC 60947-4-1, Annex F): if the main contacts weld, the NC contact stays open. So a welded SC keeps DC out, and the motor simply stays in star and never changes over. A starter stuck in star is the clue. Without that NC contact in DC’s coil circuit, DC would close onto the welded star point.
Check yourself
The timer is set to 1 s on this pump. What happens?
- It never changes over to delta and stays in star until the OL trips
- It changes over smoothly, because the star stage is short and the surge is small
- It changes over while still slow, and the second surge is close to a direct-on-line start — correct
At 1 s the motor is far below the 80–90 % speed where the changeover belongs. Delta closes on a slow rotor and draws nearly the full direct-on-line current.
What happens if SC and DC are closed at the same time?
- Nothing serious: SC and DC are in parallel and share the current
- The motor runs faster, because star and delta torques add up
- A short circuit across the phases through the star bar — correct
DC ties W2, U2 and V2 to L1, L2 and L3, and SC ties them together. Both closed means L1, L2 and L3 shorted inside the starter. The interlocks exist to stop exactly this.
Sources
- Star–delta timing relay, 50 ms changeover delay (Siemens 3RP15 catalogue)
- IEC 60947-4-1, contactors and motor-starters (IEC webstore)
- Mirror contacts to IEC 60947-4-1 Annex F (Siemens note)
For training only. Models are simplified; class rules and IMO texts are the authority.